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USPshnik [31]
2 years ago
15

The exppreson of 10x^2-7

Mathematics
1 answer:
erica [24]2 years ago
3 0

The complete question is :

Question: What is the coefficient in the expression 10x²-7?

The coefficient in the expression 10x^{2} -7 is 10

<h3>What is Coefficient?</h3>

A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

According to the question,

The expression given is 10x^{2} -7

The variable given is x

We need to find the coefficient in the expression.

In the given expression x is the variable and the number before the x is coefficient which is 10 .

Hence the coefficient in the expression is 10.

Learn more about coefficient here:

brainly.com/question/22241464

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consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
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Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

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(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
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Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
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