Find the greatest common factor of 8 and 24.

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

Factors of 8: 1, 2, 4, 8

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

They do share a few factors but the greatest one shared between the two is 8

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Miss Taylor graded 50 English research papers. Twelve of them received a grade of A. Miss Taylor drew a circle graph to display

nikdorinn [45]

<h3>Answer:</h3>

$\large\boxed{24\%}$

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to find how much percentage the circle graph is for "A" papers.

To solve this question, we would need to use information from the question.

Important information:

Graded 50 English research papers
12 of those papers had an "A" grade

With the information above, we can solve the question.

We know that there are 12 research papers that received an A and there are 50 research papers in total.

We would divide 12 by 50 in order to find the percentage of the papers that got an A.

$12\div50=24$

When you divide, you should get 24.

This means that 24% of the circle graph is devoted to "A" papers.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

3 0

3 years ago

Find the value of the constant m √150 - √12m + √54 = 0

Tomtit [17]

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>√</u><u>2</u>

Step-by-step explanation:

${ \tt{ \sqrt{150} - \sqrt{12}m + \sqrt{54} = 0 }} \\ { \tt{ \sqrt{12}m } = \sqrt{150} - \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3} m = \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times \sqrt{2} ) }} \\ { \tt{m = \sqrt{2} }}$