Step-by-step explanation:
Complete the proof of the Pythagorean theorem is given below.
Statement Reason
1. ΔABC is a right triangle, with a 1. Given
right angle at ∠C
2. Draw an altitude from point C 2. From a point not on a line, exactly
to AB one perpendicular can be drawn through the point to the line
3. ∠CDB and ∠CDA are right 3. Definition of altitude
angles
4. ∠BCA ≅ ∠BDC 4. All right angles are congruent
5. ∠B ≅ ∠B 5. 
6. ΔCBA ~ ΔDBC 6. AA Similarity Postulate
7. 
7. 
8. 
8. 
9. ∠CDA ≅ ∠BCA 9. 
10. ∠A ≅ ∠A 10.
11. ΔCBA ~ ΔDBA 11. AA Similarity Postulate
12. 
12. 
13. 
13.
14. 
14. 
15. 
15. Distributive Property
16. 
16. 
17. 
18. 
a numerical ciff3cient c constant
Formula for area of circle:
A=πr²
Here diameter, d= 6 cm
Radius, r= d/2 = 6/2 = 3 cm
Put values
A= 3.14 x 3²
A=3.14 x 9
A=28.26 cm²
Answer: 28.26 cm²
The next 3 terms would be: -14, -17, and -20 (the pattern is your -3 each time) the 100th term would be -279 i think because there is 93 spots left after the first 7 terms, so 93 x -3 = -279
Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
