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Ivanshal [37]
2 years ago
15

Given that MATH is a parallelogram, solve for c.A. 74B. 84C. 94D. 104​

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0

Answer:

C. 94

Step-by-step explanation:

Given that,

∠M = ∠T

(Opposite angles of the parallelogram)

  • b - 10 = 86°
  • b = 86 + 10
  • b = 96°

Now, ∠H + ∠T = 180°.

(Adjacent angles of the same size)

  • x + b - 10 = 180°
  • x + 96 - 10 = 180°
  • x + 86 = 180°
  • x = 180 - 86
  • x = 94°

Now, ∠H = ∠A

(Opposite angles)

  • c° = x°
  • c = 94°
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To make this a little clearer, let's give the pairs of inequalities the same denominator:

<span>Question 1: 
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First, apply the common denominator to the first fraction:
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Do the same for the second:15( \frac{5}{7}) \\  \frac{5}{7}* \frac{15}{15} \\  \frac{5*15}{7*15}  \\  \frac{75}{105}
Nest, compare the two fractions:
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Therefore:
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<span>
Question Two:</span>
\frac{5}{9} ? \frac{7}{13}
Apply the common denominator to fraction one:
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Evaluate:
\frac{65}{117} > \frac{63}{117}
Therefore:
<span>\frac{5}{9} > \frac{7}{13}
</span>
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