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Fudgin [204]
3 years ago
14

A coordinate plane. A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT p

ass through? Check all that apply. (12, 3) (–2, –5) (–3, 1) (1, 15) (5, –2)
Mathematics
2 answers:
maw [93]3 years ago
4 0

Answer: (5, -2) (-3, 1)

Step-by-step explanation: (5,-2) can't work because the y-coordinate of the answer is lower than (0, 1), while the x-coordinate is greater than (0, 1). (-3,1) can't work because the two points create a slope of 0, which is neither positive nor negative so it doesn't work. (12,3) works because it is at a higher angle and is to the upper right of the point, creating a positive slope. (-2,-5) works because it's at the lower left of the point, still a positive slope. (1,15) works because it is similar to the point (12,3), it is higher in both the x-value and the y-value of (0,1).

mario62 [17]3 years ago
4 0

Answer:

*The bolded ones are correct:

(12, 3)

(–2, –5)

(–3, 1)

(1, 15)

(5, –2)

Step-by-step explanation:

use the graph to figure this out

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What is an equation of the line that passes through (-2,3) and is parallel to y=5x + 4.Give your answer in slope intercept form
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Answer:

y= 5x+13

Step-by-step explanation:

<u>Slope- intercept form</u>

y= mx +b, where m is the gradient and b is the y-intercept.

Parallel lines have the same gradient.

y= 5x +4

Gradient of given line= 5

Thus, gradient of line= 5

Subst. m=5 into the equation.

y= 5x +b

To find the value of b, substitute a coordinate

When x= -2, y=3,

3= 5(-2) +b

3= -10 +b

b= 3 +10 <em>(</em><em>+</em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 13

Thus, the equation of the line is y= 5x +13.

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3 years ago
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Step-by-step explanation:

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