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Fudgin [204]
4 years ago
14

A coordinate plane. A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT p

ass through? Check all that apply. (12, 3) (–2, –5) (–3, 1) (1, 15) (5, –2)
Mathematics
2 answers:
maw [93]4 years ago
4 0

Answer: (5, -2) (-3, 1)

Step-by-step explanation: (5,-2) can't work because the y-coordinate of the answer is lower than (0, 1), while the x-coordinate is greater than (0, 1). (-3,1) can't work because the two points create a slope of 0, which is neither positive nor negative so it doesn't work. (12,3) works because it is at a higher angle and is to the upper right of the point, creating a positive slope. (-2,-5) works because it's at the lower left of the point, still a positive slope. (1,15) works because it is similar to the point (12,3), it is higher in both the x-value and the y-value of (0,1).

mario62 [17]4 years ago
4 0

Answer:

*The bolded ones are correct:

(12, 3)

(–2, –5)

(–3, 1)

(1, 15)

(5, –2)

Step-by-step explanation:

use the graph to figure this out

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The probability that an American company will open a location in Shanghai, China is 0.7. The probability that it will open a loc
kodGreya [7K]

Answer:

Step-by-step explanation:

Given that the probability that an American company will open a location in Shanghai, China is 0.7.

The probability that it will open a location in Beijing, China is 0.4.

The probability that it will open a location in either Shanghai or Beijing or both is 0.8.

the probability that the company will open a location in:

(a) both Shanghai and Beijing :

0.7+0.4-P(both)=0.8

P(both) = 0.3

(using addition theory of probability for union of sets)

(b) neither Shanghai nor Beijing

= 1- P(AUB)

=1-0.8 = 0.2

(c) Beijing but not in Shanghai?

P(Beiging)_P(both) = 0.4-0.3=0.1

(d) Shanghai given that it opens a location in Beijing

=P(Both)/P(Beijing) = \frac{0.3}{0.4} =0.75

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3 years ago
Write an equation for a line perpendicular to y = – 3x – 2 and passing through the point (-9,-1)
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Find the negative reciprocal of the slope of the original line and use the point-slope formula
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Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

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• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

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What is the function of the “whiskers” in a box and whisker plot?
kvv77 [185]

Answer:

the answer should be c

Step-by-step explanation:

A Box and Whisker Plot (or Box Plot) is a convenient way of visually displaying the data distribution through their quartiles. The lines extending parallel from the boxes are known as the “whiskers”, which are used to indicate variability outside the upper and lower quartiles

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3 years ago
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icang [17]
3.45 is the right answer
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3 years ago
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