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Fudgin [204]
3 years ago
14

A coordinate plane. A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT p

ass through? Check all that apply. (12, 3) (–2, –5) (–3, 1) (1, 15) (5, –2)
Mathematics
2 answers:
maw [93]3 years ago
4 0

Answer: (5, -2) (-3, 1)

Step-by-step explanation: (5,-2) can't work because the y-coordinate of the answer is lower than (0, 1), while the x-coordinate is greater than (0, 1). (-3,1) can't work because the two points create a slope of 0, which is neither positive nor negative so it doesn't work. (12,3) works because it is at a higher angle and is to the upper right of the point, creating a positive slope. (-2,-5) works because it's at the lower left of the point, still a positive slope. (1,15) works because it is similar to the point (12,3), it is higher in both the x-value and the y-value of (0,1).

mario62 [17]3 years ago
4 0

Answer:

*The bolded ones are correct:

(12, 3)

(–2, –5)

(–3, 1)

(1, 15)

(5, –2)

Step-by-step explanation:

use the graph to figure this out

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2 years ago
If alpha and beta are the zeroes of the polynomial f(x)= xsquare -8x +gamma such that alpha - beta = 2 find the value of gamma.
Komok [63]

Answer:

Γ = 15

Step-by-step explanation:

Given

f(x) = x² - 8x + Γ

with a = 1, b = - 8 and c = Γ , then

sum of zeros α + β = - \frac{b}{a} = - \frac{-8}{1} = 8

product of zeros = αβ = \frac{c}{a} = Γ

Given α - β = 2 , then

(α - β)² = 2²

α² - 2αβ + β² = 4 → (1)

and

(α + β)² = 8²

α² + 2αβ + β² = 64 → (2)

Add (1) and (2) term by term

2α² + 2β² = 68 ( divide through by 2 )

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Substitute α² + β² = 34 into (1)

34 - 2αβ = 4 ( subtract 34 from both sides )

- 2αβ = - 30 ( divide both sides by - 2 )

αβ = 15

Now

αβ = Γ = 15

Thus

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4 0
3 years ago
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Answer:

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A is the best answer…

Work:

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