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Fudgin [204]
3 years ago
14

A coordinate plane. A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT p

ass through? Check all that apply. (12, 3) (–2, –5) (–3, 1) (1, 15) (5, –2)
Mathematics
2 answers:
maw [93]3 years ago
4 0

Answer: (5, -2) (-3, 1)

Step-by-step explanation: (5,-2) can't work because the y-coordinate of the answer is lower than (0, 1), while the x-coordinate is greater than (0, 1). (-3,1) can't work because the two points create a slope of 0, which is neither positive nor negative so it doesn't work. (12,3) works because it is at a higher angle and is to the upper right of the point, creating a positive slope. (-2,-5) works because it's at the lower left of the point, still a positive slope. (1,15) works because it is similar to the point (12,3), it is higher in both the x-value and the y-value of (0,1).

mario62 [17]3 years ago
4 0

Answer:

*The bolded ones are correct:

(12, 3)

(–2, –5)

(–3, 1)

(1, 15)

(5, –2)

Step-by-step explanation:

use the graph to figure this out

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Step-by-step explanation:

We are given;

  • The quadratic equation, x² + 4x - 13 = -8

We are required to solve the equation using the completing square method.

To do this, we use the following steps;

Step 1: We make sure the coefficient of x² is one

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Step 2: Combine the like terms (take the constant term to the other side)

x² + 4x - 13 = -8

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we get

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Step 3: We add the square of half the coefficient of x on both sides of the equation

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Square of half the coefficient of x = 2² (4)

We get;

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Step 4: Put x and 2 under one square and the solve the other side of the equation.

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