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Anna35 [415]
2 years ago
15

-4/5 / 2 i still cant find the answer

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
8 0

Answer:

-2.25

Step-by-step explanation:

you gotta divide -4/5  by 2

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Hii please help i’ll give brainliest if you give a correct answer
tino4ka555 [31]

Answer:

x * 3/8(s) = 5/4

5/4 ÷ 3/8(s) = x

Step-by-step explanation:

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3 years ago
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What is theoretical vs experimental probability? Please help!
mrs_skeptik [129]

Answer:

See down below.

Step-by-step explanation:

Theoretical probability is what we expect to happen. For example, we do a test of flipping a coin. You know that its either gonna be heads or tails.

Experimental probability is what actually happens when we try it out. It occurs when we are doing an experiment and then something happens.

Hope this helps!

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3 years ago
Jake throws a dart that hits the square shown below:
mrs_skeptik [129]
21.5.......:::..............:.::.::..
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3 years ago
I need help please... I'll mark you brainiest!!! Thanks!
lys-0071 [83]

Multiply the weight in tonnes by the conversion factor ( 1 tonne = 1000 kg) to get the weight in kg's:

170 tonnes x 1000 = 170,000

Now convert to scientific notation, by moving the decimal point to have only 1 digit to the left of the decimal.

To do this, you would need to move the decimal 5 places to the left to get 1.70000

Now remove the 0's and multiply the number by 10 raised to the number of paces the decimal was moved to get:

1.7 x 10^5 kg's.

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3 years ago
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
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