Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
DE = 55
As you can see from the red marks showing that the lengths of each triangle are the same, it must also be true that E is equal to 55.
0.01 pounds is the answer
