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3 years ago

Whats this surface area?

Mathematics

2 answers:

pishuonlain [190]3 years ago

4 0

Answer:

62 sq units

Step-by-step explanation:

Area of top and bottom rectangles =

2(5x3) = 15 x 2 = 30

Area of front facing and back facing rectangle =

2(2x5) = 2 x 10 = 20

Area of side facing rectangles =

2(2x3) = 2 x 6 = 12

Total surface area = 30+20+12 = 62

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

vodka [1.7K]3 years ago

4 0

The answer is 62 square (sq) units

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2 points

saul85 [17]

Given:

Width of rectangular prism = 20 ft

height of rectangular prism = 12 ft

Length of rectangular prism = 45 ft

Cylindrical diameter = 20 ft

To find:

Volume of the tent

Solution:

Volume of the rectangular prism = length × width × height

= 45 × 20 × 12

Volume of the rectangular prism = 10800 ft³

Radius of cylinder = 20 ÷ 2 = 10 ft

Height of cylinder = length of rectangular prism

Volume of cylinder = $\pi r^{2} h$

Volume of half cylinder = $\frac{1}{2} \pi r^2h$

$$=\frac{1}{2} \times 3.142\times 10^2 \times45$

Volume of half cylinder = 7069.5 ft³

Volume of tent = volume of rectangular prism + volume of half cylinder

= 10800 ft³ + 7069.5 ft³

= 17869.5 ft³

= 17869 ft³ (nearest cubic foot)

The volume of the tent is 17869 cubic feet.

6 0

3 years ago

Will give brainliest if you are right.

miv72 [106K]

Answer:

x-int (2, 0)

y-int (0, 3)

General Formulas and Concepts:

The y-intercept is the y value when x = 0. Another way to reword that is when the graph crosses the y-axis.
The x-intercept is the x value when y = 0. Another way to reword that is when the graph crosses the x-axis.

Step-by-step explanation:

Step 1: Locate x-intercept

x-int (2, 0)

Step 2: Locate y-intercept

y-int (0, 3)

8 0

3 years ago

Can someone please help me

nadya68 [22]

Answer:

Right option is B.

Step-by-step explanation:

$\sf \longrightarrow \frac{ \sec x \sin( - x) + \tan( - x) }{1 + \sec( - x) } \\ \\ \sf \longrightarrow \frac{ \sec x( - \sin x) - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \frac{1}{ \cos x } \times \sin x - \tan x }{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \tan x - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - 2 \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{1 + \frac{1}{ \cos x} } \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} } \\ \\ \boxed{ \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1} }}$