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2 years ago

Find the slope of the line. y = -10x - 2

Mathematics

1 answer:

Pavlova-9 [17]2 years ago

6 0

The slope is the change in y-axis to x-axis of a graph. The slope of the line given is -10

<h3>How to find the slope of a line?</h3>

The standard equation of a line in slope intercept form is given as y = mx+b

where

m is the slope
b is the y-intercept

Given the equation y = -10x - 2

Compare

mx = -10x

m = -10

Hence the slope of the line given is -10

Learn more on slope here: brainly.com/question/3493733

#SPJ1

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2. Given f(x) = 5x6 - 2x3 + 7x2 + 9, state the following:

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Is it 47 huhhuhuuhhh

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3 years ago

The sum of a number and its additive inverse is equal to ___.

serious [3.7K]

The sum of a number and its additive inverse is equal to zero. E.g. an additive inverse of 2 is -2.

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3 years ago

Read 2 more answers

What’s the correct answer to this problem ?

kicyunya [14]

Answer:

y = (x+3)^2 -1

Step-by-step explanation:

The equation for an upward opening parabola is

y = a(x-h)^2 +k

Where (h,k) is the vertex

The vertex is (-3,-1)

y = a(x--3)^2 +-1

y = a(x+3)^2 -1

Put a point in to find a

(0,8)

8 = a(0+3)^2 -1

8 = a (3)^2 -1

Add 1 to each side

8+1 = a9

9=9a

Divide by 9

1 =a

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5 0

3 years ago

What is the area of the shaded portion of the circle?

SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A= $(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi$

Since $\frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}$ , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

$A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi$

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from $A_1$ .

The area of the triangle is given by

$A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2$

Thus the area of the shaded portion of the circle is

$A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2$

3 0

3 years ago

Pls help 23 points up for takeings

motikmotik

Answer:

8x5=40 the 10 dollars

Step-by-step explanation:

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3 years ago