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Leto [7]
3 years ago
13

Find the length of the hypotenuse of a right triangle whose legs are 3 and . 2

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

The answer would be 3.606, but rounded is 3.61, or 3.6

Step-by-step explanation: A^2+B^2 = c^2, so 3x3=9

2x2=4,

9+4=13

Then square 13, which would give you 3.606

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Annie has a compost pile that produces 12 pounds of compost a day from yard waste. Which function expresses the amount of compos
Masteriza [31]
The total amount of compost Annie gets is 12 every day
c equals 12 every d
c = 12d
7 0
3 years ago
Read 2 more answers
1.) Determine whether each number is irrational or rational.
nalin [4]

Answer:

1/3 is rational its nonterminating but it repeats

6.99999 rational its nonterminating and it repeats also

7.48331 is irrational because its non terminnating  and it does not repeat

Step-by-step explanation:

8 0
3 years ago
Multiply. (3.5x10^-5) (3x10^-10) express your answer in scientific notation.​
Len [333]

Answer:

5.69034 × 1011

Step-by-step explanation:

Decimal  

1234000000

Scientific Notation  

1.234 x 10^9

×10^  

9

1st Number  

1.234

×10^  

9

Operation  

2nd Number  

5.678

×10^  

11

3 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
Can someone please help me with this question.
rusak2 [61]
25x25+20x25+20x15+15x25=1800 the answer is D.
5 0
3 years ago
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