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yanalaym [24]
3 years ago
15

The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.

Mathematics
1 answer:
Olin [163]3 years ago
6 0

Answer:

h = 5\ cm

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

h = B-5.

 The area of the triangle is 25 cm²

By definition the area of a triangle is:

A = 0.5Bh

For this triangle we know that A = 25\ cm^2 and h = B-5. We substitute these values in the equation and solve for B.

25 = 0.5B (B-5)

0.5B ^ 2-\frac{5}{2}B-25 = 0

Now we use the quadratic formula to solve the equation.

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

B=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:  a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25

Then:

B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}

B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}

B=\frac{5}{2}\±\frac{15}{2}

The solutions are:

B_1=\frac{5}{2}+\frac{15}{2}=10

B_2=\frac{5}{2}-\frac{15}{2}=-5

For this problem we take the positive solution.

B=10\ cm

Now we substitute the value of B in the equation to find the height h

h = 10-5

h = 5\ cm

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Explanation:

From the given figure it is easily noticed that the shaded region contains two congruent parallelograms and 4 congruent triangles.

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The area of a parallelogram is 12 cm square.

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\text{Area of a triangle}=\frac{1}{2}\times 2\times 0.25=0.25

The area of a triangle is 0.25 cm square.

Since there are 2 parallelograms and 4 triangles in the figure, therefore the total area is,

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In circle o, the length of radius OL is 6 cm and the length
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Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

<em>As shown in the diagram;</em>

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

<em>Remember that;</em>

The length, L, of an arc is given by;

L = (θ / 360) x (2πr)         -------------(i)

Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)  

Where;

L = length of arc LM = 6.3cm

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<em>Substitute these values into the equation to get;</em>

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π)              [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = \frac{6.3*30*7}{22}

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Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° =  135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)  

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation;</em>

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L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

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