Answer:
Yes.
Step-by-step explanation:
Just like normal algebra, you factor our the common factor, in this case, 5.
Thus,
![\sin(5(x + 4))](https://tex.z-dn.net/?f=%20%5Csin%285%28x%20%2B%204%29%29%20)
Answer: she is NOT correct the answer should be X= 19
How?:
the equation was 5x = 95
the 5 and x is being multiplied the opposite of multiplication is dividing
so 95/5= 19
therefor x= 19 and NOT 90
Answer:
Step-by-step explanation:
Rate = 56 gal / 7 min
= 8 gal / min
Answer:
Following are the solution to this question:
Step-by-step explanation:
They provide various boxes or various objects. It also wants objects to be distributed into containers, so no container is empty. All we select k objects of r to keep no boxes empty, which (r C k) could be done. All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining
objects. All can be put in any of k boxes. Therefore, these
objects could in the
manner are organized. Consequently, both possible ways to do this are
![=\binom{r}{k} \times k! \times k^{r-k}\\\\=\frac{r! \times k^{r-k}}{(r-k)!}](https://tex.z-dn.net/?f=%3D%5Cbinom%7Br%7D%7Bk%7D%20%5Ctimes%20k%21%20%5Ctimes%20k%5E%7Br-k%7D%5C%5C%5C%5C%3D%5Cfrac%7Br%21%20%5Ctimes%20k%5E%7Br-k%7D%7D%7B%28r-k%29%21%7D)
Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one
![= \frac{r!k^{r-k}}{(r-k)!}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Br%21k%5E%7Br-k%7D%7D%7B%28r-k%29%21%7D)
Answer:
try 4
Step-by-step explanation:
8x4= 32
32-7=25