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3 years ago

What is true if a pair of parallel lines are rotated

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

They are still parallel, no matter how they are two parallel lines always remain parallel.

Hope that was helpful

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In NEED OF HELP! SO Frustrating!

vitfil [10]

ja, yo is correct, just expand that formula with your calculator

each one is 5% bigger than pevious

each one=previous+previous*5%

each one=previous*1+previous*0.05

each one=previous*(1+0.05)

each one is 1.05 times of previous

so after n years, if today year size is P then

$A=P(1.05)^n$

A=final size

so ya, after 18 years, n=18 so you get

$A=859(1.05)^{18}$

A=2067.29 microliters

6 0

3 years ago

Help please I’m almost done also I’ll mark brainliest

tatuchka [14]

Answer:

this is a ratio of 4 inches:5 feet.

if one side becomes 30 feet, means that other one is also multiplied by 6.

4 * 6 = 24 or A

pls mark as brainliest

Step-by-step explanation:

4 0

3 years ago

What’s the slope and equation

Pie

Y=-10x-100

Rise over run

5 0

3 years ago

Read 2 more answers

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

3 years ago

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu

iVinArrow [24]

Answer:

$-0.061 < P_1 -P_2< 0.025$

Step-by-step explanation:

Give data:

$n_1 = 350$

$n_2 =250$

$x_1 = 23$

$x_2 = 21$

$\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066$

$\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084$

for 95% confidence interval

$\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025$

$z_{\alpha/2} = 1.96$ from standard z- table

confidence interval for P_1 and P_2 is

$\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}$

$(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}$

$-0.018 \pm 0.043$

confidence interval is

$-0.018 - 0.043 < P_1 -P_2$

$-0.061 < P_1 -P_2< 0.025$

7 0

3 years ago