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drek231 [11]
3 years ago
9

How do you solve (2x^5)(6x^4)

Mathematics
1 answer:
Grace [21]3 years ago
8 0
First expand the brackets by multiplying each thing inside the brackets by 2:
4x−10=6x+4. then minus the 4x so there are only x 's on one side:
−10=2x+4. then minus the 4 so there are only numbers on one side and x 's on the other:
−14=2x. then divide by 2 to get the value of x
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Solve each equation.<br> 1)<br> 9c + 1 = 10
Vinvika [58]

Answer:

doesnt c = 1

Step-by-step explanation:

I don't even know I'm just tryna get points

3 0
3 years ago
Please solve this 4 the grade algebra problem? A group of students calculated their average score at a spelling bee. They realiz
In-s [12.5K]
Let x = original average score
let y = be the number of students

We need to write two equation using the information given in the scenario in order to work them simultaneously and obtain the results.

let \frac{yx  +   9}{y}  =  81 .... (1)
     so x is the original average, so we multiply that average by the amount of     students [y × x] in order to obtain their cumulative score then you add the       nine to that score (because a student got 9 more points) [yx + 9]. Then you    divide that sum by the amount of student in  order to get the new average      which the question says would be 81

\frac{yx  -  3}{y}  =  78 ...... (2)
   so x is the original average, so we multiply that average by the amount of     students [y × x] in order to obtain their cumulative score then you subtract       three from that score since one student got three less points [yx - 3].  Then     you divide by the number of students (y) and you should 78 like the                 question says.

\frac{yx + 9}{y} = 81 .... (1)
\frac{yx - 3}{y} = 78 ...... (2)

Now simplify each equation by separating the LHS
\frac{yx}{y}  +   \frac{9}{y}  = 81..... (1a)
\frac{yx}{y} - \frac{3}{y} = 78...... (2a)

By subtracting eq (2a) from eq (1a) in order to eliminate x
\frac{yx}{y} - \frac{yx}{y} + \frac{9}{y} - (- \frac{3}{y}) = 81 - 78

\frac{12}{y} = 3

\frac{12}{3} = y

⇒ y  =  4

Since y = the number of students
then  the number of students = 4




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3 years ago
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Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
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Number line of put them in order from least to greatest .
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