Answer:
25 cm^2
Step-by-step explanation:
the area of 1 triangle is 20, so the missing length of the triangle is 5. 5x5=25
Answer:
about 22.2 feet
Step-by-step explanation:
The wire can run diagonally across the floor and, from the intersection with the wall, diagonally up the wall. The total length is computed per the hint to be ...
d = √(18^2 +13^2) = √493 ≈ 22.20 . . . . feet
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If the wire were to go up the short wall, its length would be ...
d = √(11^2 +20^2) = √521 ≈ 22.83 . . . . feet
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<em>Comment on the attachment</em>
The red represents the floor; the green represents the long wall.
- A rectangle has a perimeter of 44 inches and an area of 72 square inches.
- Perimeter = 44 inches, area = 72 square inches.
- Let the length and breadth be l and b respectively.
- We know, perimeter of a rectangle = 2(l + b)
- Therefore,
- 2(l + b) = 44
or, l + b = 22
or, b = 22 - l ...(i)
- We know, area of a rectangle = lb
- Therefore,
- lb = 72
- Putting (i) in b, we get
- l(22 - l) = 72
or, 22l - l^2 -72 = 0
or, l^2 - 22l + 72 = 0
or, l^2 - 4l - 18l + 72 = 0
or, l(l - 4) - 18(l - 4) = 0
or, (l - 4)(l - 18) = 0
or, l = 4 or l = 18
- Therefore, if the length is 4 inches, then the breadth is (22-4) inches, i.e., 18 inches.
- And if the length is 18 inches, then the breadth is (22-18) inches, i.e., 4 inches.
<u>Answer:</u>
<u>B)</u><u> </u><em><u>4</u></em><em><u> </u></em><em><u>inches </u></em><em><u>and </u></em><em><u>1</u></em><em><u>8</u></em><em><u> </u></em><em><u>inches.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Part A: the area of a rectangle is A= lw, so
A= lw
Height= 6x+3.= 9x
Width= 8
Which makes the expression to this area 9x x 8 ( 9x times 8 )
Part B: you do the same to get the expression here, so the expression would be
6x x 12 ( 6x times 12 )
The answer to this part is yes because both end up being 72x once you get the answer of each.