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3 years ago

Select three ratios that are equivalent to 4:3 Choose 3 answers:

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

Answer:

Ratios that are equivalent are: 8:6, 20:15 and 32:24

Step-by-step explanation:

There are more, but those are some that I found :)

postnew [5]3 years ago

6 0

Ratios equivalent to 4:3 would be 8:6 16:12 and 24:18

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Please answer!!!!!!!!!!!!!!!!!

laiz [17]

The answer is B, the green is f(x)=x^2 and the red one is g(x)=f(2x).

4 0

2 years ago

Find the distance between points P(1, 2) and Q(4, 8) to the nearest tenth. i neeeeeed help

Stella [2.4K]

The answer is
the vector PQ has (4-1, 8-2) as components, so it is vecPQ= (3, 6)
using the definition
the distance PQ= sqrt ( 3²+6²)= sqrt(9+36)=sqrt(45)

5 0

2 years ago

The water in a reservoir decreased by 47% during a drought. Before the drought, the reservoir held 44,580 acre ft (AF) of water.

RSB [31]

44,580 x 47 %

44,580 x .47 = 20,952.6

So, the water decreased 20,952.6 ft

If you want the water level after the drought just subtract.

44,580 - 20,952.6 = 23,627.4 ft

Hope this helps. :)

5 0

3 years ago

Find the solutions to the system of equations. Select all that apply. Y=x^2-1 y=2x-2

Sliva [168]

Answer:

Option C (1, 0)

Step-by-step explanation:

We have a system with the following equations:

$y = x ^ 2-1\\\\y = 2x-2$

The first equation is a parabola.

The second equation is a straight line

To solve the system, substitute the second equation in the first and solve for x.

$2x-2 = x ^ 2 -1$

Simplify

$x ^ 2-2x + 1 = 0$

You must search for two numbers that when you add them, obtain as a result -2 and multiplying both results in 1.

These numbers are -1 and -1

Therefore

$x ^ 2-2x + 1= (x-1)(x-1)\\\\x ^ 2-2x + 1= (x-1)^2=0$

Finally the solutions are

$x = 1\\y =0$

8 0

3 years ago

Read 2 more answers

An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.

Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0. $\overline 1$ yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0. $\overline 1$ yd. = (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel pad, m₁ = ρ × V₁

∴ The mass of the steel pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0

3 years ago