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S_A_V [24]
2 years ago
6

Solve Multi-Step Equations, Part 2 - Instruction

Mathematics
2 answers:
Citrus2011 [14]2 years ago
4 0

Answer:

g = -0.5 or -1/2

Step-by-step explanation:

-10(g – 6) = 65 : apply distributive property

(-10 • g) + (-10 • -6) = 65 : multiply

-10g + 60 = 65 : apply property of equal subtraction

-10g + 60 – 60 = 65 – 60 : subtract

-10g = 5 : apply property of equal division

-10g ÷ -10 = 5 ÷ -10 : divide

g = -0.5

Irina18 [472]2 years ago
3 0

Answer:

g = -0.5

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve.

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Kay [80]

Answer:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by V= 10 +t

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}

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We find the solution using the integration factor:

\mu = -\int \frac{1}{10+t} dt = -ln(10+t)

And then the solution would be given by:

A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})

And if we simplify this we got:

A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)

And after do the integral we got:

A= \frac{c}{10+t} +4 (10 +t)

And using the initial condition t=0 A= 20 we have this:

20 = \frac{c}{10} +40

c= -200

So then we have this function for the solution of A:

A= \frac{-200}{10+t} +4 (10 +t)

And now replacinf t= 40 we got:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

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