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gladu [14]
3 years ago
12

A set of 9 numbers has a mean of 20. What additional number must be included in this set to create a new set with a mean that is

4 less than the mean of the original set?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0

<em>Greetings from Brasil...</em>

The average for a set of 9 elements will be

(A + B + C + D + E + F + G + H + I) ÷ 9 = 20

Let's make (A + B + C + D + E + F + G + H + I) like S

<em>(I chose S to remember a sum)</em>

Let us think.....

S ÷ 9 = 20

S = 20 × 9

S = 180

So,  (A + B + C + D + E + F + G + H + I) = 180

According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:

<h3>(A + B + C + D + E + F + G + H + I + J) ÷ 10 = (20 - 4)</h3>

as seen above, (A + B + C + D + E + F + G + H + I) = 180, then

(180 + J) ÷ 10 = 16

(180 + J) = 160

J = 160 - 180

<h2>J = - 20</h2><h2 />

So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16

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3 years ago
Write 15+45 as a product of two factors using the gcf and the distributive property
valkas [14]

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5 0
2 years ago
1. Find "V". Round to hundreds.<br>V = LWH<br>L= 29.4<br>W = 16.7<br>H = 21.8​
postnew [5]

Volume = 10,700

V = LWH

L = 29.4

W = 16.7

H = 21.8

All we need to do is multiply them all together and then round the answer to get our final answer to the hundreds place.

V = LWH

V = 29.4(16.7)(21.8)

V = 490.98(21.8)

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Then, we need to round it to the hundreds place.

V = 10,700

4 0
3 years ago
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