-- Start with 86.
-- Subtract 9 the first time. You have 77 left.
-- Subtract 9 the 2nd time. You have 68 left.
-- Subtract 9 the 3rd time. You have 59 left.
-- Subtract 9 the 4th time. You have 50 left.
-- Subtract 9 the 5th time. You have 41 left.
-- Subtract 9 the 6th time. You have 32 left.
-- Subtract 9 the 7th time. You have 23 left.
-- Subtract 9 the 8th time. You have 14 left.
-- Subtract 9 the 9th time. You only have 5 left, so you can't subtract 9 again.
You subtracted it 9 times, and you have 5 left.
So 86 divided by 9 is (9 with remainder 5) .
X is bigger than 65 but smaller or equal to 69. Looks a bit like this...6569.
(However “>“ is a little different as there should be a line under it to show how it can be equal to 69.
You can build a square shape I'm not sure but I think this it hopes it helps!:)
Use the slope formula: m = rise/run.
Try to solve using this formula.
So you want to set up an equation for a weighted average. You know the final is 30% of the grade, so everything else is 70%. This gives you:
(Final)(.30) + (other grades)(.70) = course grade
The best grade the student can get would be if they get a hundred on the final, since that’s the best score you can make on the final. Then,
(100)(.30) + (82)(.70) = course grade
30 + 57.4 = course grade = 87.4 Which, If you round, the student would get an 87.
For the last part, we use the same equation, just filling in different parts.
(Final)(.30) + (other grades)(.70) = course grade
This time, we don’t know the grade for the final, but we know the course grade.
(Final)(.30) + (82)(.70) = 75
(Final)(.30) + 57.4 = 75
(Final)(.30) = 17.6
Final = (17.6)/(.30)
Final = 58.667 Which is approx a 59.
