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3 years ago

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one orange and one apple cost 1.05, two oranges and three apples cost $2.75, how much do two apples cost?

1 answer:

Nimfa-mama [501]3 years ago

5 0

If you would like to know how much do two apples cost, you can calculate this using the following steps:

o ... the cost of one orange
a ... the cost of one apple

1 * o + 1 * a = $1.05
2 * o + 3 * a = $2.75
_______________
o + a = 1.05 ... o = 1.05 - a
2 * o + 3 * a = 2.75
2 * (1.05 - a) + 3 * a = 2.75
2.1 - 2 * a + 3 * a = 2.75
a = 2.75 - 2.1
a = $0.65

o = 1.05 - a = 1.05 - 0.65 = $0.4

2 * a = 2 * 0.65 = $1.3

The correct result would be: Two apples cost $1.3.

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Alchen [17]

Answer:

a) Sale Price; Rs. 800 Discount rate: 20%

b) Sale Price; Rs. 4000 Discount rate: 20%

c) Sale Price; Rs. 6000 Discount rate: 35%

Step-by-step explanation:

1. Approach

In these problems, one is given a list of original prices and the amount of price taken off during a discount. One has to find the sale price and the rate of discount. The easiest way to find the sale price is to subtract the discount price from the original price. The general train of thought to do this can be found in the following formula:

$(original\ price)-(discount\ amount)=(sale\ price)$

One is also asked to find the rate of discount. Use the following proportion format to do so:

$\frac{discount\ amount}{original\ price}=\frac{percent}{100}$

Substitute each of the values in the given problem into the equation and solve for the price.

2. Part A

Original price: 1000

Discount: 200

<u>1. Sale price</u>

Formula
$(original\ price)-(discount\ amount)=(sale\ price)$
Substitute and solve,
$1000-200=(sale\ price)$

$\\800 = sale\ price$

<u>2. Discount rate</u>

Formula

$\frac{discount\ amount}{original\ price}=\frac{percent}{100}$

Substitute, simplify, and solve

$\frac{200}{1000}=\frac{percent}{100}$
$\frac{1}{5}=\frac{percent}{100}$

$(5)(percent)=1(100)$
$percent=20$

3. Part B

Original price: 5000

Discount: 1000

<u>1. Sale price</u>

Formula,
$(original\ price)-(discount\ amount)=(sale\ price)$
Substitute and solve
$5000-1000=(sale\ price)$
$4000=(sale\ price)$

<u>2. Discount rate</u>

Formula
$\frac{discount\ amount}{original\ price}=\frac{percent}{100}$
Substitute, simplify, and solve
$\frac{1000}{5000}=\frac{percent}{100}$
$\frac{1}{5}=\frac{percent}{100}$
$5(percent)=1(100)$

$percent=20$

4. Part C

Original price: 8000

Discount: 2000

<u>1. Sale price</u>

Formula
$(original\ price)-(discount\ amount)=(sale\ price)$
Substitute and solve
$8000-2000=(sale\ price)$
$6000=(sale\ price)$

<u>2. Discount rate</u>

Formula,
$\frac{discount}{amount}=\frac{percent}{100}$
Substitute, simplify and solve,
$\frac{2000}{8000}=\frac{percent}{100}$
$\frac{1}{4}=\frac{percent}{100}$
$4(percent)=1(100)$
$percent=25$

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