2 years ago

Evaluate the algebraic expression. y^2+x+y when x=-3 and y=-4

Mathematics

1 answer:

Amanda [17]2 years ago

5 0

Step-by-step explanation:

you put the values in place of the variable names and calculate.

y² + x + y

(-4)² + -3 + -4 = 16 - 3 - 4 = 16 - 7 = 9

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A sector of a circle of 7cm has an area of 44cm².calculate the angle of the sector,correct to the nearest degree π =22\7

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Answer:

$\theta=102.85^{\circ}$

Step-by-step explanation:

Given that,

The radius of circle, r = 7 cm

The area of sector, A = 44cm²

We need to find the angle of the sector. The formula for the area of sector is given by :

$A=\dfrac{\theta}{360}\pi r^2$

Solve for $\theta$ .

$\theta=\dfrac{360A}{\pi r^2}\\\\\theta=\dfrac{360\times 44}{\dfrac{22}{7}\times 7^2}\\\\\theta=102.85^{\circ}$

So, the angle of the sector is equal to $102.85^{\circ}$ .

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