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Serga [27]
2 years ago
11

Solve pls brainliest

Mathematics
2 answers:
Tema [17]2 years ago
7 0

Answer:

1. 13

2. 10

Step-by-step explanation:

<h2><u><em>Brainliest Please!</em></u></h2>
satela [25.4K]2 years ago
4 0

Answer:

13 and 10

Step-by-step explanation:

You might be interested in
Calculate the value of angle A and C of ∆ ABC. Where b=1435cm, a= 782cm and B= 115.6°.​
Monica [59]

The Law of Sines says

\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}

\sin A = \dfrac a b \sin B

A = \arcsin( \dfrac{782}{1435} \sin 115.6 ) = 29.44^\circ

We don't have to worry about the obtuse supplement because a triangle can only have one obtuse angle, and that's B.

C = 180 - 115.6 - 29.44 = 34.96^\circ

Answer: A=29.44°, C=34.96°

5 0
3 years ago
What is the rational number that is equivalent to a -24 / -6
saw5 [17]

Answer:

4

Step-by-step explanation:

hi! let's divide -24 and -6 to simplify this. this is the same answer as 24/6 since two negatives that are divided by each other equal a positive number, and 24 divided by 6 is 4, so the answer is 4.

5 0
3 years ago
PLEASE HELP MEE
Snowcat [4.5K]

Answer:

Option A= 250

Step-by-step explanation:

Coterminal angles are angles in standard positions having thesame terminal .

Coterminal angles are always negative and positive.

For example:

The coterminal angle of 30° is-

30 - 360 = -330

30 + 360 = 390

Therefore, -330 and 390 are coterminal.

So, to the question:

The angles between 0 -360 coterminal to -110 is 250.

Prove:

250 - 360 = -110

250 + 360 = 610

Option A is correct

5 0
3 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
I need help plzzzzzzzz
mixer [17]

Answer:

31

51

201

151

Step-by-step explanation:

Addition and subtraction

7 0
3 years ago
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