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2 years ago

: Compute the 9 partial derivatives for the network with two inputs, two neurons in

Computers and Technology

1 answer:

lions [1.4K]2 years ago

8 0

Using the python code we can say that it will be possible to calculate the neutrons and organize them as:

<h3>The code can be written as:</h3>

def get_total_derivative(self,l_id):

def sigmoid(x, div = 0):

if div == 1:

return np.exp(-x) / (1. + np.exp(-x))**2.

if div == 2:

return - np.exp(x) * (np.exp(x) - 1) / (1. + np.exp(x))**3.

return 1. / (1. + np.exp(-x))

def linear(x, div = 0):

if div == 1:

return np.full(x.shape,1)

if div > 2:

return np.zeros(x.shape)

return x

See more about python at brainly.com/question/18502436

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Here's something to stop you from getting repetitive when writing essays. Write a program that reads multiple lines of plain tex

Marianna [84]

Answer:

The output is attached below

Explanation:

d = {}

while True:

line = input("Enter line: ")

if len(line)==0:

break

token = line.split(' ')

for var in token:

try:

if len(var)==0:

continue

count = d[var]

d[var] = count + 1

except KeyError:

d[var] = 1

pass

for word in sorted(d):

print(word , d[word])

------------------

7 0

3 years ago

Convert the following numbers from decimal to binary, assuming unsigned binary representation:________.

kumpel [21]

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

$\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\ 2 & 17 & 1 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1\end{tabular}\end{center}$

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

$\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\ 2 & 1 & 1 \\ \end{tabular}\end{center}$

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

$\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\ 2 & 13 & 1 \\ 2 & 6 & 0 \\ 2 & 3 & 1 \\ 2 & 1 & 1 \end{tabular}\end{center}$

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

$\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1 \\\end{tabular}\end{center}$

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

8 0

3 years ago

Which feature of a blog allows an author to interact and get feedback from his or her readers? link pingback commenting TweetMem

poizon [28]

Commenting. When someone comments of a blog the blog's writer can comment back, to answer questions, etc.

6 0

3 years ago

A network administrator was told by the Chief Information Officer (CIO) to set up a new office with a network that has redundanc

balandron [24]

Answer:

"Mesh topology" is the correct answer.

Explanation:

A mesh topology seems to be a network configuration where there has been an interconnection between each hardware and communications system. This topology configuration allows the distribution of many of these signals, although one of the connexons starts going down.
This topology needs to connect each destination to any other end destination, thus creating a completely pointless channel.

3 0

3 years ago

Suppose you have a 16-bit machine with a page size of 16B. Assume that any unsigned 16-bit integer can be a memory address. Also

irinina [24]

Answer:

2^11

Explanation:

Physical Memory Size = 32 KB = 32 x 2^10 B

Virtual Address space = 216 B

Page size is always equal to frame size.

Page size = 16 B. Therefore, Frame size = 16 B

If there is a restriction, the number of bits is calculated like this:

number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]

where

physical memory size = 32KB which is the restriction

n bit machine = frame size = 16

Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11

7 0

3 years ago