The digital libraries address the problem of digital exclusion by: They reach out to people who need technology and help teach them digital literacy skills.
<h3>What does it mean to be digitally excluded?</h3>
The digital exclusion is known to be also as digital divide and this is known to be where a part of the population is known to possess a continuous and unequal access and capacity in regards to the use Information and Communications Technologies (ICT),
Note that IT are very essential for all to be fully participated in the society and the digital libraries address the problem of digital exclusion by: They reach out to people who need technology and help teach them digital literacy skills.
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Explanation:
"Select vendor_name as Vendor_Name,
default_account_number as Default_Account_No ,
account_description as Account_Description
From Vendors v, General_Ledger_Accounts ledger
where (add the join condition here)
Order by account_description, vendor_name"
Note: In the above statement, include the alias name appropriately and then execute the query
The "select statement" should contain the list of columns to be displayed
"From statement" should contain the name of the table from which data needs to be fetched.
"Where clause" defines the relationship as well the condition that needs to be executed
"Order by clause" defines the sorting mechanism with the relevant field
Answer:
The answer to this question is given below in the explanation section
Explanation:
This question contains six securities terms and definitions.
The goal of this question is to properly map the term to its correct description/definition.
You can find the complete mapping in the attached image.
Answer:
Explanation:
The following is written in Python. It takes in a file, it then reads all of the elements in the file and adds them to a list called myList. Then it sorts the list and uses the elements in that list to calculate the median. Once the median is calculated it returns it to the user. The code has been tested and the output can be seen in the image below.
def find_median(file):
file = open(file, 'r')
mylist = []
for number in file:
mylist.append(int(number))
numOfElements = len(mylist)
mylist.sort()
print(mylist)
if numOfElements % 2 == 0:
m1 = numOfElements / 2
m2 = (numOfElements / 2) + 1
m1 = int(m1) - 1
m2 = int(m2) - 1
median = (mylist[m1] + mylist[m2]) / 2
else:
m = (numOfElements + 1) / 2
m = int(m) - 1
median = mylist[m]
return median
print("Median: " + str(find_median('file1.txt')))
