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aksik [14]
2 years ago
13

Robyn adopted a child who is exactly 28 years younger than her.

Mathematics
1 answer:
lesya [120]2 years ago
8 0
If Robyn’s age is r then her child is r-28.
In one year Robyn will be r+1 and her child r-27
r + 1 = 3(r - 27)
r + 1 = 3r - 81
r - r + 1 + 81 = 3r - r - 81 + 81
82 = 2r
r = 41
Robyn is 41 years old
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