1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksi-84 [34.3K]
2 years ago
6

For year y, the population of massachusetts was approximately what percent of the population of vermont?

Mathematics
1 answer:
kifflom [539]2 years ago
5 0

Answer: 50%

Step-by-step explanation:  50%

You might be interested in
I need c and d answered badly
Kisachek [45]

C. translated down 2 units

---The "-2" located on the outside of f(x) tells us that the y-values are being changed. With that, the graph can be moved up or down. The presence of the negative/subtraction sign tells us that the graph is moved down.

D. translated right 4 units

---The "-4" located with the x in f(x) tells us that the x-values are being changed. The only tricky thing about this is that the direction of the movement is actually the opposite of the sign. So with the negative/subtraction sign, the graph is moved to the right instead of the left.

Hope this helps!

3 0
2 years ago
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
3 years ago
Meep says meep so what's the meep of the meep
Alex17521 [72]

Answer: ok so meep is gunna meep to the meep power of meep and 6 more meeps

Step-by-step explanation:

i got it right when i looked it up lol

6 0
3 years ago
tim spent 24 at the grocery store this was six dollars less than two timeswhat he spent at the game store how much did he spend
Svetlanka [38]
Money spent at grocery store = x, money spent at game store = y
x = 24
x = 2y - 6

24 = 2y - 6
24 + 6 = 2y
30 = 2y
30/2 = y
15 = y <=== spent 15 at game store

4 0
3 years ago
Can someone help me make an inequality?<br><br> Problem: Eight less than a number X is at least 17
ioda
Set up an inequality: 
x-8\geq17
x\geq25
8 0
3 years ago
Other questions:
  • Select all the names for a in the expression.
    6·2 answers
  • Tierra bought 4 3/8 yards of blue ribbon and 2 1/8 for a craft project how much more blue ribbon than yellow ribbon did Tierra b
    8·1 answer
  • How do i write 98.5 in scientific notation?
    12·1 answer
  • The high temperature was 92°F. This was 24°F higher than the overnight low temperature. Write an equation to determine whether t
    11·2 answers
  • The value of a two-digit number exceeds twice the sum of its digits by 19. The tens digit is two less than the units digit. Find
    10·1 answer
  • Find the vertex of parabola y=-2x^2-20x-48
    13·2 answers
  • This hanger is in balance. There are two
    14·2 answers
  • Find the product of -2x a(-4x b - 2x 3 + 5x)
    6·1 answer
  • Someone help me find the answer to this problem. 15a - 20 + 10a =
    8·2 answers
  • Solve the Antiderivative.​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!