4,880,000
hope that helps!!
Answer:

Step-by-step explanation:
Given


Required:
Calculate the angle between u and v
The angle
is calculated as thus:

For a vector


becomes




For a vector


So;






So:






Take arccos of both sides





<em></em>
<em> (approximated)</em>
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
Well, the most reasonable explanation would be j+8 or 8+j
Answer:
Step-by-step explanation:
The pressure is equal to the atmospheric pressure 101 kN/m plus 8 kN/m for every meter below the surface, therefore;
a. expression for pressure is given by,
............................... (1)
where d = depth below the surface in meter.
b. to find the depth at any pressure, equation (1) above is rearranged to make depth (d) subject of the formula

as an example, to find depth at pressure of 200N/m
d = (200 - 101)/8 = 12.375 meters
depth is 12.375 meters below the surface.