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Gala2k [10]
2 years ago
11

The expression x-y equals 0.7 if x and y have certain values. Evaluate the following expression with the same values of x and y

Mathematics
1 answer:
Arisa [49]2 years ago
7 0

Answer:

<h2>3.5</h2>

Step-by-step explanation:

<h2>We already know that x-y equals to 0.7,</h2><h2>so 5(x-y) would just be 5(0.7), with this the answer would equal to 3.5. </h2>

<em>***I hope this helps and the explanation is helpful!***</em>

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Hello there can you please help me posted picture of question
mario62 [17]
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If you observe the options you can see that polynomial shown in option A is only listed in descending order i.e. starting from a maximum exponent of x and then moving towards lower exponents of x.

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6 0
3 years ago
Collectively, what are the interest costs and other fees for using a credit card called? A. balance B. credit line C. finance ch
stealth61 [152]

The correct answer is C. Finance charge

Explanation:

A credit card is a service offered by financial entities such as banks that allows customers to buy goods and pay them later. This implies the customer does not immediately for goods but pays for these after a specific time. The use of this benefit implies related costs such as fees for the use of the credit card, and interest costs (money charged for borrowing the money from the bank), which are known as finance charge or the money charged for the benefit of using credit. According to this, the correct answer is C.

8 0
3 years ago
In the xy-plane, the line x + y=k, where k is a constant, is tangent to the graph of y=x^2+3x+1. What is the value of k?
Talja [164]
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k = -3

4 0
3 years ago
the measures of two angles of a parallelogram are 120 and 40 find the other angles guys please answer urgent​
insens350 [35]
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8 0
2 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \\ \\ y=m_{2}x+b \\ \\1=-\frac{1}{ 3} \cdot3 + b

1=-1+b\\ \\ b=1+1\\ \\b=2 \\ \\ y =- \frac{1}{3}x+2


6 0
3 years ago
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