All categories

2 years ago

A bakery sells 5 apple muffins for every 2 bran muffins sold . Which table shows this ratio

Mathematics

2 answers:

DENIUS [597]2 years ago

7 0

We are given here that for every 2 bran muffins that the bakery is selling , it also sells 5 apple muffins.

So we can write the ratio of apple muffins to bran muffins as :

Apple muffins : Bran muffins = 5:2

In fraction form it can be written as :

$\frac{Apple muffins}{Bran muffins} = \frac{5}{2}$

Answer : Ratio is Apple muffins : Bran muffins = 5:2

Elan Coil [88]2 years ago

3 0

It would be 5:2. 5 apple to 2 bran

You might be interested in

Select all ratios equivalent to 18:10<br><br>36:20<br>9:5<br>27:15

vfiekz [6]

All of them are correct

3 0

3 years ago

Read 2 more answers

If you built a model of the Empire State Building that is proportional to the real building. The height of the Empire State Buil

tangare [24]

Let’s see now, there are 600 inches in 50 feet.
12in = 1ft, 12in * 50 = 600.
Which means the model you’ll be making will be a 1:600 ratio model. If we find out how many inches are in 1,250 feet, and divide that number by 600, we will get our answer.
1,250 * 12 = 15,000.
So 1,250 feet equate to 15,000 inches. Now we must divide 15,000 by 600.
15,000 ÷ 600 = 25.
So your model will be 25 inches (or 2’1” [2 feet & 1 inch] tall).

7 0

2 years ago

If BcA, AnB=(1,4,5)and AuB= (1,2,3,4,5,6) find B?

Marrrta [24]

Hello,

if B ⊂ A then A∩B=B

So B={1,4,5}

7 0

2 years ago

2.5 -5.9n - 3n +5.....?

SpyIntel [72]

-8.9n+7.5
would be your answer

8 0

2 years ago

A scrap metal dealer claims that the mean of his sales is "no more than $80," but an Internal Revenue Service agent believes the

Artyom0805 [142]

Answer:

There is enough not evident to support dealer's claim that his sales is no more than $80.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $80

Sample mean, $\bar{x}$ = $91

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = $21

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 80\text{ dollars}\\H_A: \mu > 80\text{ dollard}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{91 - 80}{\frac{21}{\sqrt{20}} } = 2.3425$

Now, $t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = 1.729$

Since,

The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

There is enough not evident to support dealer's claim that his sales is no more than $80.

4 0

3 years ago