The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is
seconds
So, the time required for 200 wing beat
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
![200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds](https://tex.z-dn.net/?f=200t%3D1%20%5C%5C%20%5C%5C%20t%3D%5Cfrac%7B1%7D%7B200%7Dseconds%5C%5C%20%5C%5C%20t%3D%20%28%5Cfrac%7B1%7D%7B200%7D%2A1000%20%29milliseconds%5C%5C%20%5C%5C%20t%3D%28%205%20%29milliseconds)
So, the time required for one wing beat is 5 milliseconds.
Answer:
$100 + $10<em>m</em>
Step-by-step explanation:
A = Account Balance = 100
After M months
A = $100 + $10m
Answer:
B and F
Step-by-step explanation:
The surface area of the square pyramid will be 78.08 square inches.
<h3>What is surface area?</h3>
The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called the surface area.
<h3 />
Given that:-
Sara purchased a porcelain sculpture that is in the shape of a square pyramid. The slant height is 6.1 inches and the base is 6.4 inches. The surface area will be.
The surface area of the square pyramid will be calculated by the formula:-
![SA = P\times\dfrac{l}{2}](https://tex.z-dn.net/?f=SA%20%3D%20P%5Ctimes%5Cdfrac%7Bl%7D%7B2%7D)
![SA = 25.6\times \dfrac{6.1}{2}](https://tex.z-dn.net/?f=SA%20%3D%2025.6%5Ctimes%20%5Cdfrac%7B6.1%7D%7B2%7D)
SA = 78.08 square inches
Therefore the surface area of the square pyramid will be 78.08 square inches.
To know more about a surface area follow
brainly.com/question/23773586
#SPJ1