Answer:

Step-by-step explanation:
<u>SOH CAH TOA</u>
Where:
s = sin
c = cos
t = tan
o = opposite
a = adjacent
h = hypotenuse
cos = 2/3 where 2 is adjacent side and 3 is hypotenuse, now find opposite side using a^2 + b^2 = c^2 //c is hypotenuse side
2^2 + b^2 = 3^2
4 + b^2 = 9
b^2 = 9 - 4
b^2 = 5
b = square root (5) = 5^(1/2) //opposite side
sin = O/H

//Hope it helps.
i believe the answer is , k ≥ −18 , i’m not sure tho
The area of the square is:

And the area of the circle is:
![\begin{gathered} Ac=\pi r^2 \\ Ac=\pi\cdot(3\sqrt[]{2})^2 \\ Ac=18\pi \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Ac%3D%5Cpi%20r%5E2%20%5C%5C%20Ac%3D%5Cpi%5Ccdot%283%5Csqrt%5B%5D%7B2%7D%29%5E2%20%5C%5C%20Ac%3D18%5Cpi%20%5Cend%7Bgathered%7D)
The area of one segment is given by: