4 years ago

Quick help meeeeeeeeeeeeeee!!!!!1.Which equation has a graph that is parallel to the graph of 2x - 3y = 1?

Mathematics

1 answer:

andreev551 [17]4 years ago

8 0

1.) A
2.) A
3.) D
Those r the answers

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How do the graphs of the functions f(x)=<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B2%7D%29%5Ex" id="TexFormula1" titl

grin007 [14]

Step-by-step explanation:

f(x) = (3/2)ˣ

g(x) = (2/3)ˣ

These are examples of exponential equations:

y = a bˣ

If b > 1, the equation is exponential growth.

If 0 < b < 1, the equation is exponential decay.

So f(x) is an example of exponential growth, and g(x) is an example of exponential decay.

Also, 2/3 is the inverse of 3/2, so:

g(x) = (3/2)^(-x)

So more specifically, f(x) and g(x) are reflections of each other across the y-axis.

5 0

3 years ago

Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side

svp [43]

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6

Last, we have all the information needed in order to calculate the area by the formula:

$A = \frac{(AB + CD)DH}{2}$

A = (7 + 5) × 2√6 ÷ 2
= 12√6

The area of the regular trapezoid is 12√6 square units.