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lubasha [3.4K]
2 years ago
13

La ecuación h(x) =23 es lineal?

Mathematics
1 answer:
NARA [144]2 years ago
7 0
Si! H(x)=23 es lineal
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You are driving in a car with your brother and your sister. As you approach the next corner, your brother tells you to turn left
Reika [66]

Answer:  d. mutually exclusive

Step-by-step explanation:

Mutually exclusive events are those events that cannot happen at the same time. If one event happens, the other has a zero chance of happening at the same time.

Event A and Event B here are Mutually Exclusive because you cannot turn left and right at the same time. If you listen to your brother and turn left, you cannot also listen to your sister and turn right at the same time.

5 0
4 years ago
Find the slope (m) and y-intercept (b) of 3x + y = -18
Pepsi [2]
Slope intercept form: y=-3x-18
3 0
3 years ago
what’s transformation is the result of reflect in the original figure across the Y-axis and then across the X-axis
antoniya [11.8K]

Answer:

D

Step-by-step explanation:

When reflected across the Y it becomes B, but then across the X, it fits into D.

3 0
3 years ago
Let R be the region bounded by
loris [4]

a. The area of R is given by the integral

\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36

b. Use the shell method. Revolving R about the x-axis generates shells with height h=x+6-7\sin\left(\frac{\pi x}2\right) when 1\le x\le 2, and h=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With radius r=x, each shell of thickness \Delta x contributes a volume of 2\pi r h \Delta x, so that as the number of shells gets larger and their thickness gets smaller, the total sum of their volumes converges to the definite integral

\displaystyle 2\pi \int_1^2 x \left((x + 6) - 7\sin\left(\dfrac{\pi x}2\right)\right) \, dx + 2\pi \int_2^{22/7} x\left((x+6) - 7(x-2)^2\right) \, dx \approx 129.56

c. Use the washer method. Revolving R about the y-axis generates washers with outer radius r_{\rm out} = x+6, and inner radius r_{\rm in}=7\sin\left(\frac{\pi x}2\right) if 1\le x\le2 or r_{\rm in} = 7(x-2)^2 if 2\le x\le\frac{22}7. With thickness \Delta x, each washer has volume \pi (r_{\rm out}^2 - r_{\rm in}^2) \Delta x. As more and thinner washers get involved, the total volume converges to

\displaystyle \pi \int_1^2 (x+6)^2 - \left(7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \pi \int_2^{22/7} (x+6)^2 - \left(7(x-2)^2\right)^2 \, dx \approx 304.16<em />

d. The side length of each square cross section is s=x+6 - 7\sin\left(\frac{\pi x}2\right) when 1\le x\le2, and s=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With thickness \Delta x, each cross section contributes a volume of s^2 \Delta x. More and thinner sections lead to a total volume of

\displaystyle \int_1^2 \left(x+6-7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \int_2^{22/7} \left(x+6-7(x-2)^2\right) ^2\, dx \approx 56.70

7 0
2 years ago
Before the celebration for
Minchanka [31]

Answer:

1,165\frac{1}{3}\ yd

Step-by-step explanation:

In this problem we have a regular octagonal barrier (That means that all the length side are equal)

Find out the perimeter of the barrier

The perimeter is equal to

P=8b

where

b is the length side of the barrier

we have

b=145\frac{2}{3}\ yd= 145+\frac{2}{3}=\frac{437}{3}\ yd

substitute in the formula of perimeter

P=8(\frac{437}{3})=\frac{3,496}{3}\ yd

Convert to mixed number

\frac{3,496}{3}\ yd=\frac{3,495}{3}+\frac{1}{3}=1,165\frac{1}{3}\ yd

3 0
3 years ago
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