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2 years ago

Simplify the expression completely.

Mathematics

1 answer:

weeeeeb [17]2 years ago

6 0

The solution of the given expression $\sqrt{7xy^7}\sqrt{21x^5y^5}$ will be 7x³y⁶√3.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expression will be solved as follows:-

E = $\sqrt{7xy^7}\sqrt{21x^5y^5}$

E = $\sqrt{7\times 7\times 3\times xy^7\times x^5y^5$

E= $\sqrt{7\times 7\times 3\times x^6y^{12}$

E = 7x³y⁶√3.

Therefore the solution of the given expression $\sqrt{7xy^7}\sqrt{21x^5y^5}$ will be 7x³y⁶√3.

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3 years ago

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Answer:

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Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

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2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

+2xy+y

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3 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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4 Expand by distributing terms.

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5 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x

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3 years ago

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3 years ago