Answer:
The coach can do this in 3,003 ways
Step-by-step explanation:
Here, the coach needs to select a team of 5 from a total of 15 players
Mathematically, the number of ways this can be done is simply 15 C5 ways
Generally, if we are to select a number of r items from n items, this can be done in nCr ways = n!/(n-r)!r!
Applying this to the situation on ground, we have;
15C5 = 15!/(15-5)!5! = 15!/10!5! = 3,003 ways
I guess that u = μ & that a=σ. If so:
μ =100 & that σ =20 & x=20
Z score = (x-μ) / σ ==> Z score = (90-100)/20 ==> Z = - 0.5
Answer:
0.7999989281
Step-by-step explanation:
x1 = cos^-1 (3/5)
x1= 53.13°
sin(53.13) = 0.7999989281
Alright, so if we divide fractions we get
(x/y)/(a/b)= (x/y)*(b/a). If the x is 5 and the a is 6, as well as y and b being the same therefore cancelling out, we can write it easily. For example, we can write (5/100)/(6/100) or (5/60)/(6/60)
