Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
The answer is 30
Step-by-step explanation:
If you were to do 50% of 30, it would be 15 students that are girls. There's 18 students that are girls though, so the extra 10% would make 18 students in the class girls. The remaining 40% would be 12 boys. So basically you're taking 10% from one side and putting it in the other because 50% of 30 is 15 (well this is at least how I would do it, I don't know how others would do it though)
Answer:
2
The y intercept is the point at which a line crosses the y axis. In the graph the y axis is crossed at 0, 2 or just 2
Step-by-step explanation:
Answer:
2m+2=16, then do the isolate m but doing the inverse operation of 2 which is now -2 and add that to 16 would be left with 2m=14 and 14/2 is 7 so m=7
Step-by-step explanation:
