<span> m + n^2
= 2 + (-2)^2
= 2 + 4
= 6
answer is 6</span>
Answer:
![\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D%5Ccdot%5Csqrt%5B3%5D%7B5%7D%20%3D%5Csqrt%5B6%5D%7B5%5E3%7D%20%5Ccdot%5Csqrt%5B6%5D%7B5%5E2%7D%20%3D%5Csqrt%5B6%5D%7B5%5E5%7D%20%3D5%5E%7B%285%2F6%29%7D)
Step-by-step explanation:
The rules of exponents apply, even when they are fractional exponents:
![a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}](https://tex.z-dn.net/?f=a%5Eb%5Ccdot%20a%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%5Csqrt%5Bb%5D%7Bx%5Ea%7D%3Dx%5E%7B%28a%2Fb%29%7D)
Answer:
26.6 repeating a line should be over the 6 couldn't figure out how to do on my phone or 26.66666666666666
Step-by-step explanation:
80 divide by 3 26.6 repeating 9 minus 3 is 6 6 divide 160 is 26.6 repeating 21 minus 9 is 12 12divided by 320 is 26.6 repeating
639293!47,behdjdkevejskksnsbwjajMsbdhcifmensbjxocnfndoxold
hlo I am ram and my frn is shyam how are you I am also fine here