Answer:
a). m∠AED = 70°
b). x = 10°
Step-by-step explanation:
a). Quadrilateral ABDE is a cyclic quadrilateral.
Therefore, by the theorem of cyclic quadrilateral,
Sum of either pair of opposite angle is 180°
m(∠AED) + m(∠ABD) = 180°
m(∠AED) = 180° - 110°
m(∠AED) = 70°
Since, ∠AED ≅ ∠EAD
Therefore, m∠AED = m∠EAD = 70°
b). By triangle sum theorem in ΔABD,
m∠ABD + m∠BDA + m∠DAB = 180°
110° + 40° + m∠DAB = 180°
m∠DAB = 180° - 150°
m∠DAB = 30°
m∠BAE = m∠EAD + m∠BAD
= 70° + 30° = 100°
By angle sum theorem in ΔACE,
m∠EAC + m∠AEC + m∠ACE = 180°
100° + 70° + x° = 180°
x = 180° - 170°
x = 10°
It’s c. Where the two planes intersect
Answer:
Domain: [3, ∞)
Range: [-1, ∞)
Step-by-step explanation:
lmk if you want an explanation
Here are the basic rules for a right triangle:
One angle is always 90° or right angle.
The side opposite angle 90° is the hypotenuse.
The hypotenuse is always the longest side.
The sum of the other two interior angles is equal to 90°.
The other two sides adjacent to the right angle are called base and perpendicular.
a quick way to find angle 1, is just to look at the figure. there seems to be bisecting angles, so angle FCE and angle 1 are congruent. (meaning angle 1 is also 34 degrees)
hope this helps! lmk.
