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BaLLatris [955]
3 years ago
12

Rewrite the expression without the negative exponent. 1/x^−8 (this is a fraction)

Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

I believe the answer is x^8

Step-by-step explanation:

move x^-8 to the numerator in 1/x^-8 using the negative exponent rule 1/b-n = b^n.

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If (x^2+1)/x = 7 find x^2+(1/x^2)
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Answer:

x²+(1/x²) = 47

Step-by-step explanation:

by identity : (a+b)² = a²+b²+2ab

(x+1/x)²= x²+(1/x)²+2(x)(1/x)

(x+1/x)²= x²+(1/x²)+2....(1)

since : (x²+1)/x = 7

(x²/x) +(1/x) = 7

x + (1/x )= 7

put the value for : x +(1/x) in (1) :

49 = x²+(1/x²)+2

x²+(1/x²) = 47

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3 years ago
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7/8
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