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Talja [164]
2 years ago
7

Whats the polynomial of (7x+7)(x+2)

Mathematics
2 answers:
STALIN [3.7K]2 years ago
7 0

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

will you be my friend

Step-by-step explanation:

.......... okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Jlenok [28]2 years ago
7 0
(7x+7)(x+2)
= 7x^2 + 14x + 7x + 14
= 7x^2 + 21x + 14
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An article in a women's magazine says that women who choose to nurse their babies feel warmer and more receptive toward the infa
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5 0
3 years ago
Find the x-intercepts of the parabola with
tia_tia [17]

Answer:

(\frac{1}{2},0),(\frac{3}{2},0)

Step-by-step explanation:

The vertex form of a parabola is given by:

y=a(x-h)^2+k, where V(h,k) is the vertex of the parabola.

The given parabola has vertex (1,1).

This implies that: h=1,k=1.

Put these values into the vertex form equation.

\implies y=a(x-1)^2+1

The y-intercept of this parabola is: (0,-3).

This point lies on the parabola hence it must satisfy its equation.

\implies -3=a(0-1)^2+1

\implies -3=a(-1)^2+1

\implies -3=a(1)+1

\implies -3=a+1

\implies -3-1=a

\implies -4=a

The equation now becomes

\implies y=-4(x-1)^2+1

To find the x-intercept, put y=0 into the equation:

\implies -4(x-1)^2+1=0

\implies -4(x-1)^2=-1

Divide through by -4.

\implies \frac{-4(x-1)^2}{-4}=\frac{-1}{-4}

\implies (x-1)^2=\frac{-1}{-4}

\implies (x-1)^2=\frac{1}{4}

Take plus or minus square root of both sides.

\implies x-1=\pm \sqrt{\frac{1}{4}}

\implies x-1=\pm \frac{1}{2}

\implies x=1\pm \frac{1}{2}

\implies x=1-\frac{1}{2} or \implies x=1+ \frac{1}{2}

\implies x=\frac{1}{2} or \implies x=1 \frac{1}{2}

Therefore the x-intercepts are:

(\frac{1}{2},0),(\frac{3}{2},0)

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7 0
4 years ago
The legs of a right triangle are 6.0 and 5.5, what is the
bogdanovich [222]

Answer:

D

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So here, let’s say the hypotenuse is d.

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d = √(66.25)

d = 8.14

4 0
3 years ago
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