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myrzilka [38]
2 years ago
14

Prove that sin4a+2sin2acos2a+cos4a=1 ​

Mathematics
1 answer:
Sav [38]2 years ago
7 0

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \: \sin {}^{4} ( \alpha)  + 2 \sin {}^{2} ( \alpha)  \cos {}^{2} ( \alpha) +  { \cos {}^{4} ( \alpha) }^{}

\qquad❖ \:  \sf \:( \sin {}^{2} ( \alpha) ) {}^{2}  + 2( \sin {}^{2} ( \alpha))(  \cos {}^{2} ( \alpha)) +  {( \cos {}^{2} ( \alpha)) }^{}

( use identity a² + 2ab + b² = (a + b)² )

\qquad❖ \:  \sf \:( {\sin {}^{2}( { \alpha}) + \cos {}^{2} ( \alpha)) }^{2}

( sin² x + cos ² x = 1 )

\qquad❖ \:  \sf \: {1}^{2}

\qquad❖ \:  \sf \: {1}^{}

\qquad \large \sf {Conclusion}  :

Value of that expression is 1

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Answer:

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makvit [3.9K]

Answer:

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Step-by-step explanation:

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