Your answer would be 8 Hammond per minute. Hope this helps!
Answer:
slope = -3/2
y-int = 3
Step-by-step explanation:
3x + 2y = 6
-3x -3x
2y = -3x +6
/2 /2 /2
y = -3/2 + 3
Answer:
As per the statement:
The path that the object takes as it falls to the ground can be modeled by
h =-16t^2 + 80t + 300
where
h is the height of the objects and
t is the time (in seconds)
At t = 0 , h = 300 ft
When the objects hit the ground, h = 0
then;
-16t^2+80t+300=0
For a quadratic equation: ax^2+bx+c=0 ......[1]
the solution for the equation is given by:
![x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
On comparing the given equation with [1] we have;
a = -16 ,b = 80 and c = 300
then;
![t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B-80%5Cpm%20%5Csqrt%7B%2880%29%5E2-4%28-16%29%28300%29%7D%7D%7B2%28-16%29%7D)
![t= \frac{-80\pm \sqrt{6400+19200}}{-32}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B-80%5Cpm%20%5Csqrt%7B6400%2B19200%7D%7D%7B-32%7D)
Simplify:
= -2.5 sec and
= 7.5 sec
Time can't be in negative;
therefore, the time it took the object to hit the ground is 7.5 sec
Answer:
1.92755 ,1.870320 i hope it will help you