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zheka24 [161]
3 years ago
14

the average of johnnys two tests is a 92. what must he get to on a third test to raise his average to a 94

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
N=3 tests and the average is 94
3*94= 282
92+92 (add the average scores) = 184
282-184=98
He needs a 98 to raise his average to a 94

Hopefully this helps...
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The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

#SPJ4

4 0
2 years ago
Consider a data set containing the following values: 70 65 71 78 89 68 50 75 The mean of the preceding values is 70.75. The devi
Leokris [45]

Answer:

If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18

If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46

Step-by-step explanation:

We are given the following data-set:

70, 65, 71, 78, 89, 68, 50, 75

Deviations from the mean

–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2

Sample size, n = 8

Sample:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

s = \sqrt{\dfrac{875.5}{7}} = 11.18

\text{ Sample variance} = s^2 = 125.07

Population:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46

\text{ Population variance} = \sigma^2 = 109.44

7 0
3 years ago
HELP PLEASEEEE I don’t get it
jek_recluse [69]

10 is answer choice B

11 is answer choice A

7 0
3 years ago
Read 2 more answers
ed is using the recipe shown to make fruit salad he wants to use 30 diced stawberries in his vruit sald how many bananas apples
Leya [2.2K]
We know that 1 serving = 4 bananas 
3 apples
6 pears
and 20 strawberrys
To get 30 we need to half 20 =10    20+10=30

That means we also needs to half the other ones
1/2 of 4 = 2   4+2=6
1/2 of 3 = 1.5 3+ 1.5=4.5
1/2 of 6 = 3  6+3=9

6 Bananas
4.5 Apples
9 Pears
30 strawberries diced.
6 0
3 years ago
Read 2 more answers
What’s the equation of the midline?<br> Determine an equation for this graph<br><br> ASAP
choli [55]

Answer:

y = -cos(2x)

Step-by-step explanation:

Mean/mid line: y = 0

It's a negative cos, with period pi.

So, y = -cos(2x)

7 0
3 years ago
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