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zheka24 [161]
2 years ago
14

the average of johnnys two tests is a 92. what must he get to on a third test to raise his average to a 94

Mathematics
1 answer:
ASHA 777 [7]2 years ago
8 0
N=3 tests and the average is 94
3*94= 282
92+92 (add the average scores) = 184
282-184=98
He needs a 98 to raise his average to a 94

Hopefully this helps...
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A home gardener estimates that 24 apple trees will have an average yield of 104 apples per tree. But because of the size of the
d1i1m1o1n [39]

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

Trees = 24

Yield = 104

x \to additional\ trees

So, we have:

Trees = 24 + x

Yield = 104 - 2x

Required

The additional trees to be planted for maximum yield

The function is:

f(x) = Trees * Yield

f(x) = (24 + x) * (104 - 2x)

Open bracket

f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x

f(x) = 2796 + 104x - 48x - 2x^2

f(x) = 2796 + 56x - 2x^2

Rewrite as:

f(x) = - 2x^2 + 56x + 2796

Differentiate

f'(x) = -4x + 56

Equate f'(x) = -4x + 56 to 0 and solve for x to get the maximum of x

-4x + 56 = 0

-4x =- 56

Divide by -4

x =14

The farmer should plant 14 additional trees, for maximum yield.

5 0
3 years ago
Which of the following best describes a chord?
Alinara [238K]

Answer:

The Answer is A, a line segment that has both endpoints on a circle.

Step-by-step explanation:

5 0
3 years ago
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If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?
aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = 185 \div 2

= 92.5 calories

So, the amount of calories burnt in 3 miles = 3 \times 92.5

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0
3 years ago
Read 2 more answers
Question 1
Alexxx [7]

Answer:

Water needed for pool = 486 cubic feet

Plastic liner required for the pool = 298.3 feet

Step-by-step explanation:

Top view of the pool is a composite figure, having one rectangle and a trapezoid.

1). Water needed for the pool = volume of the pool

Volume of the pool = Area of the base × Depth

                               = (Area of the rectangle + Area of the trapezoid)× depth  

Area of the trapezoid = \frac{1}{2}(b_{1}+b_{2})\times h

                                    = \frac{1}{2}(11+9)\times (12-1.5)

                                    = 105 ft²

Area of the rectangle = Length × width

                                    = 11 × 1.5

                                    = 16.5 ft²

Now, volume of the pool = (105 + 16.5) × 4

                                          = 121.5 × 4

                                          = 486 cubic feet

b). Liner required = surface area of the pool excluding top

                             = Surface area of the walls + Area of the pool base

                             = (Perimeter of the pool) × depth + area of the base

                             = (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5

                             = 176.8 + 121.5

                             = 298.3 square feet

Therefore, amount of water required = 486 cubic feet

liner needed = 298.3 square feet                                  

8 0
2 years ago
Solve the inequality x+2 1/2 >-1/2.graph the solution set on a number line. Show your work.
Ainat [17]

Answer:

x > -11

Step-by-step explanation:

The way fractions type on here are weird, so i typed it on a different website i think this is right though.

4 0
2 years ago
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