Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
9514 1404 393
Answer:
x = 14
Step-by-step explanation:
The sum of angles in a triangle is 180°:
∠O +∠P +∠Q = 180°
(2x -5)° +(3x -8)° +(10x -17)° = 180°
15x -30 = 180 . . . . . divide by °, collect terms
x -2 = 12 . . . . . . . . . divide by 15
x = 14 . . . . . . . . . . . .add 2
i would say B
when it says "the measure", it's refering to where the second quartile is beginning
