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3 years ago

What is an example of equasions when you are given the constant of poportionality

Mathematics

1 answer:

alexandr1967 [171]3 years ago

4 0

Answer:

The constant of proportionality is the ratio between two directly proportional quantities. In our tomato example, that ratio is $3.00/2, which equals $1.50. Two quantities are directly proportional when they increase and decrease at the same rate.

Step-by-step explanation:

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Plz show work to get brainliest

gogolik [260]

Answer:

45 students speak Spanish at Francis Lewis High School

Step-by-step explanation:

Option1:

$\frac{72}{400} = \frac{x}{250}$

18000 = 400x

x = 45 students speak Spanish at Francis Lewis High School

Option2:

72 ÷ 400 = 0.18

0.18 * 250 = 45 students speak Spanish at Francis Lewis High School

4 0

3 years ago

Solve the following equation by completing the square. 12x^2 - 48x = -39

daser333 [38]

Answer:

$\large\boxed{\boxed{x = \begin{cases} \frac{ \sqrt{3} }{2} + 2 \\ - \frac{ \sqrt{3} }{2} + 2 \end{cases}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
PEMDAS

<h3>let's solve:</h3>

$\sf divide \: both \: sides \: by \: 12 : \\ \sf {x}^{2} - 4x = - \frac{13}{4}$
$\sf \: add \: { - 2}^{2} \: to \: both \: sides : \\ \sf { {x}^{2} } - 4x + ( - {2}^{2} ) = \frac{13}{4} + ( { - 2}^{2} ) \\ {x}^{2} - 4x + 4 = \frac{13}{4} + 4$
$\sf simplify \: addition : \\ \sf { {x}^{2} } - 4x + 4 = \frac{3}{4}$
$\sf use \: {a}^{2} - 2ab + {b}^{2} = (a - b {)}^{2} : \\ \sf (x - 2 {)}^{2} = \frac{3}{4}$
$\sf squre \: root \: both \: sides : \\ \sf \sqrt{(x - 2 {)}^{2} } = \pm \sqrt{ \frac{3}{4} } \\ \begin{cases} x - 2 = \frac{ \sqrt{3} }{2} \\x - 2 = - \frac{ \sqrt{3} }{2} \end{cases}$
$\sf add \: 2 \: to \: both \: sides : \\ \sf \begin{cases}x = \frac{ \sqrt{3} }{2} + 2 \\ x = - \frac{ \sqrt{3} }{2} + 2 \end{cases} \\ \therefore \: x = \begin{cases} \frac{ \sqrt{3} }{2} + 2 \\ - \frac{ \sqrt{3} }{2} + 2 \end{cases}$

7 0

3 years ago

Read 2 more answers

Help please just this 1-5 please answer correctly but real people only answer correctly I'll do anything

jekas [21]

Answer: Check the answers below

Step-by-step explanation:

Remember: slope is rise/run

1) 3/15 = 0.2 ft

2) 4/3

3) 2

4) 6/8

5) 2/9

3 0

3 years ago

Find an equation of the plane. the plane through the point (2, 0, 5) and perpendicular to the line x = 7t, y = 6 − t, z = 4 + 5t

My name is Ann [436]

Given:
P: (2,0,5)
L: (0,6,4)+t(7,-1,5)
and required plane, Π , passes through P and perpendicular to L.

The direction vector of L is V=<7,-1,5>.
For Π to be perpendicular to V, Π has V as the normal vector.

The equation of a plane with normal vector <7,-1,5> passing through a given point P(xp,yp,zp) is
7(x-xp)-1(y-yp)+5(z-zp)=0

Thus the equation of plane Π passing through P(2,0,5) is
7(x-2)-y+5(z-5)=0
or alternatively,
7x-y+5z = 14+25
7x-y+5z = 39

4 0

3 years ago

Help me! Answer in pic not correct !

sladkih [1.3K]

Answer:

$Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)$