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4 years ago

Answerrr.................

Mathematics

1 answer:

Zigmanuir [339]4 years ago

5 0

Answer:

3rd option

Step-by-step explanation:

brainliest?:(

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5. What would the graph of y= 3/4x -7/8 look like?

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A curve is the answer

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3 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

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3 years ago

HELP PLEASE!<br> Line 1 is parallel to line 2. Which of the following statements is true?

bixtya [17]

Letter J is correct

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3 years ago

Please help :) 25 points

sasho [114]

Answer:

They're all acute angles

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3 years ago

Read 2 more answers

The line containes the point (-8,11) and has a y intercept of 5

kicyunya [14]

Step-by-step explanation:

Since, line contains the point (-8, 11) and has a y intercept of 5.

Therefore, line passes through the points (-8, 11) and (0, 5)

Equation of line in two point form is given as:

$\frac{y-y_1 }{y_1 - y_2 } = \frac{x-x_1 }{x_1 - x_2 } \\ \\ \therefore \: \frac{y-11 }{11 - 5 } = \frac{x-( - 11) }{ - 11 - 0 } \\ \\ \therefore \: \frac{y-11 }{6 } = \frac{x + 11 }{ - 11 } \\ \\ \therefore \: - 11(y-11 )=6 (x + 11) \\ \\ \therefore \: - 11y + 121=6 x + 66 \\ \\ \therefore \: 0=6 x + 11y + 66 - 121 \\ \\ \red{ \boxed{\therefore \: 6 x + 11y - 55 = 0}}$

Hence, 6x + 11y - 55 = 0 is the required equation of line.

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3 years ago