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zvonat [6]
1 year ago
9

Angle sum theory find Y

Mathematics
1 answer:
kompoz [17]1 year ago
4 0
<h3>Answer:</h3>

25

<h3>Step-by-step explanation:</h3>

The angle sum theory says that the sum of all the interior angles in a triangle is 180 degrees.

Finding X

To solve for y, we must first find x. This way we know 2 of the interior angles. Luckily, angle x is a part of a linear pair.

  • Linear Pairs are 2 adjacent angles that create a straight line together. This means that the sum to 180 degrees.

Angle x and the angle with a measurement of 115 form a linear pair. Thus, we can create an equation to find x.

  • 115 + x = 180

By subtracting 115 from both sides we know that x = 65.

Solving for Y

Now that we know x, we can find y. We know that one of the interior angles is 65 and that the other is 90 degrees. The square marking the bottom angles in the middle show that they are right angles.

  • Right angles are usuaslly denoted with a square drawn in the angle and have a measurement of 90 degrees.

Lastly, we can create a formula to find y with the angle sum theory.

  • 90 + 65 + y = 180

Combine like terms

  • 155 + y = 180

Subtract 155 from both sides

  • y = 25

This means that the angle y is 25 degrees.

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Which shows how to solve the equation Three-fourths x = negative 6 for x in one step?
tino4ka555 [31]

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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

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⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
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