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2 years ago

Mr ramos thumb measures 4 cm. Express this length in meters

2 answers:

4 0

Hello! The answer would be 0.04 meters. You find this by doing so.
100cm=1m
4cm=?
100/4=25, 1/25=0.04. Remember, what you do to one side, you do to the other.

Alika [10]2 years ago

3 0

Hello There!

Mr. Ramos thumb measures 0 meters. 100cm=1m

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A nutritionist is interested in estimating the proportion of consumers who look to purchase organic produce. How large of a samp

olga2289 [7]

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2 years ago

Solve 0 = (x – 4)2 – 1 by graphing the related function.

fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

$y=\left(x-\:4\right)^2-1$

Finding the x-intercept by substituting the value y = 0

$y=\left(x-\:4\right)^2-1$

$\:0\:=\:\left(x\:-\:4\right)^2\:-\:1$ ∵ y = 0

$\left(x-4\right)^2-1=0$

$\left(x-4\right)^2-1+1=0+1$

$\left(x-4\right)^2=1$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$\mathrm{Solve\:}\:x-4=\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=1$

$x=5$

$\mathrm{Solve\:}\:x-4=-\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=-1$

$x=3$

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0

3 years ago

Patrice goes to fishers candy shop with the price of gummy candies modeled by the equation y=5/2x where x is the amount of gummy

icang [17]

Answer:

You need to put the question, but I'll try to help as much as I can without the question. y=5/2x, if you put the amount of gummy candy in lbs in the x's place, and you multiply the amount by 5/2, you will get the price.

Step-by-step explanation:

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3 years ago

In the following expression, both A and B are variables that can take positive values.

krok68 [10]

I think the answer is A and C!

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2 years ago

Help please!!!!!!!!!!!

kvasek [131]

Answer:

B. 2/3

Step-by-step explanation:

To solve this we have to take into account this axioms:

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Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.

Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.

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3 years ago