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3 years ago

Mr ramos thumb measures 4 cm. Express this length in meters

2 answers:

4 0

Hello! The answer would be 0.04 meters. You find this by doing so.
100cm=1m
4cm=?
100/4=25, 1/25=0.04. Remember, what you do to one side, you do to the other.

Alika [10]3 years ago

3 0

Hello There!

Mr. Ramos thumb measures 0 meters. 100cm=1m

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For the following geometric sequence find the recursive formula and the 5th term in the sequence. In your final answer, include

Sophie [7]

...42, -193.. thats the 4th and 5th Hope this helps

7 0

3 years ago

Read 2 more answers

Can Somebody Please Explain How To Do It? THANKS

sergejj [24]

Hello from MrBillDoesMath!

Answer:

Discussion:

Solution 1:

Distance between two points (x1, y1), (x2,y2) is given by the formula

sqrt( (x1-x2)^2 + (y1-y2)^2). In our case this becomes

sqrt( (0-0)^2 + (12 -3)^2 ) =

sqrt( 9^2) =

Solution 2:

Note points D and E both have x = 0 so segment DE is a vertical segment. The length is simply the difference of the y coordinates: 12- 3 = 9 as before.

Thank you,

MrB

6 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x, y =

miss Akunina [59]

Answer:

381.18 cubic units

Step-by-step explanation:

Graph the region:

desmos.com/calculator/iwvreqjz2m

The region is a trapezoid. When we rotate it about x = 1, we get a hollow cylinder shape. We can either use washer method or shell method to find the volume.

If we find the volume using washer method, we'll have to use two integrals, one for the triangular part of the trapezoid and one for rectangular part. If we use shell method, we only need one integral. So let's use shell method.

Cut a thin, vertical slice of the region. The width of this slice is dx. The height of the slice is y₂ − y₁ = x − 0 = x. The radius of the shell is x − 1.

The volume of the shell is:

dV = 2π (x − 1) (x) dx

dV = 2π (x² − x) dx

The total volume is the sum of all the shells from x=5 to x=7.

V = ∫ dV

V = ∫₅⁷ 2π (x² − x) dx

V = 2π ∫₅⁷ (x² − x) dx

V = 2π (⅓ x³ − ½ x² + C) |₅⁷

V = 2π [(⅓ 7³ − ½ 7² + C) − (⅓ 5³ − ½ 5² + C)]

V = 2π [⅓ 7³ − ½ 7² − ⅓ 5³ + ½ 5²]

V = 2π [⅓ (7³ − 5³) + ½ (5² − 7²)]

V = 2π [⅓ (218) + ½ (-24)]

V = 2π (72⅔ − 12)

V = 121⅓ π

V ≈ 381.18

The volume is approximately 381.18 cubic units.

6 0

3 years ago

Two supplementary angles are in the ratio 3 1 : 5 find both angles

Zielflug [23.3K]

The two angles are 155 degrees and 25 degrees

<h3><u>Solution:</u></h3>

Given that two supplementary angles are in ratio 31 : 5

Let the first angle be 31a

Let the second angle be 5a

Two Angles are Supplementary when they add up to 180 degrees.

Therefore,

first angle + second angle = 180 degrees

$31a + 5a = 180\\\\36a = 180\\\\a = \frac{180}{36}\\\\a = 5$

<em><u>Therefore the angles are:</u></em>

first angle = 31a = 31(5) = 155 degrees

second angle = 5a = 5(5) = 25 degrees

Thus the two angles are 155 degrees and 25 degrees

3 0

3 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

2 years ago