X^2+4x=-3
x^2+4x+3=0
(x+1)(x+3)=0
x+1=0 so x=-1
x+3=0 so x=-3
so the solution is x=-3,-1
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Answer:
<h2><em>
(3,6)</em></h2>
Step-by-step explanation:
Given two coordinates (x₁,x₂) and (y₁,y₂), their midpoint (w,y) is expressed as:
M(X,Y) = 
From the question, we are given the midpoint (X,Y) to be (2,2) and one endpoint as (1, -2) and we are to find the other end point expressed as (w,y). From the coordinates given, i can be seen that X = 2, Y =2, x₁ = 1 and y₁ = -2
Substituting the given end points into the given formula to get the other end points, we will have;

Similarly;

<em>Hence the other endpoint (w, y) is (3,6)</em>
<span>A system of equations has infinitely many solutions when the two
lines representing the equations coincide. i.e. the two equations are
the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
2y = 2(2x + 3)
y = 2x + 3
-y = -(2x + 3)
-y = -2x - 3
Hence the other equation is -y = -2x - 3</span>