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hjlf
1 year ago
9

Amy is x years old. Ben is 2 years older than Amy. Alice is six years younger than Amy.

Mathematics
2 answers:
mezya [45]1 year ago
8 0

<u>Answer:</u>

a)

Amy's age is <em>x</em>.

• Ben's age is 2 more than Amy's age.

∴ Ben's age = <em>x </em>+ 2

• Alice's age is 6 less than Amy's age.

∴ Alice's age = <em>x </em>- 6

Art [367]1 year ago
7 0

Answer:

Step-by-step explanation:

Amy = x years

Ben = x + 2  (years)

Alice = x - 6 (years)

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nasty-shy [4]

Answer:

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7 0
3 years ago
What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21
docker41 [41]

The linear equation that is perpendicular to the line x+3y=21 is:

y = 3*x - 6

<h3>How to find the equation of the line?</h3>

A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

x +3y = 21

3y = 21 - x

y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

m*(-1/3) = -1

m = 3

our line is:

y = 3*x + b

To find the value of b, we use the fact that our line passes through (1, - 3)

-3 = 3*1 + b

-3 - 3 = b

-6 = b

The line is y = 3*x - 6

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brainly.com/question/1884491

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3 0
1 year ago
amina bought an air cooler for a AED 3300 including VAT of 5% find the price of the air cooler before VAT was added
wlad13 [49]

Answer:

$3142.86

Step-by-step explanation:

3300 --> 105%

x --> 100%

criss cross method

x=330000/105

x=3142.86

7 0
2 years ago
Please help me with math
Marat540 [252]

The area of triangle BMN is 124.7 square centimeter.

<h3>What are similar triangles?</h3>

Similar triangles are triangles that their corresponding angles are equal and the ratio of their corresponding lengths are equal. They are often similar When at least Two angles are equal or The ratio of any corresponding lengths are same.

Analysis:

AB = AC = BC = 50cm

AH = AC/2 = 50/2 = 25cm

From Δ ABH, using Pythagoras theorem to find BH.

(BH)^{2} = (AB)^{2} - (AH)^{2}

(BH)^{2} = 50^{2} - 25^{2}

(BH)^{2} = 2500 - 625

(BH)^{2} = 1875

BH = \sqrt{1875} = 43.3cm

ΔBMN and BHC are similar,

so, BM/BH = MN/HC

BM/43.3 = 12/25

25BM = 12 X 43.3

BM = 519.6/25 = 20.78cm

Area of ΔBMN

= 1/2(MN)(BM) = 1/2 x 12 x 20.78 = 124.7 square centimeter

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4 0
1 year ago
Please Help - Suppose f(t)=6t−8−−−−√.
Gnoma [55]

(a)\\\\\\\text{Given that,}~~\\\\ f(t) =\dfrac 6{\sqrt{t-8}}\\\\\\\\\implies f'(t) = 6\left[\dfrac{\left(\sqrt{t-8}\right) \cdot 0 - \dfrac 1{2\sqrt{t-8 }}}{\left(\sqrt{t-8}\right)^2}\right]\\\\\\\\\implies f'(t) = -6\left(\dfrac {\dfrac 1{2\sqrt{t-8}}}{t-8}\right)\\\\\\\implies f'(t) = -6\left(\dfrac{1}{2\sqrt{t-8} (t-8)}\right)\\\\\\\implies f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}

(b)

\text{Given that,}\\\\y=f(t)\\\\\text{Slope of  y,} ~~ f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}\\\\\text{At point  (33, 6/5)}\\\\\\f'(t) = -\dfrac 3{(33-8)^{\tfrac 32}} = - \dfrac 3{ (25)^{ \tfrac 32}} = - \dfrac 3{5^3} = -\dfrac 3{125}\\\\\\\text{Equation with given points,}\\\\y - \dfrac 65 = -\dfrac 3{125} ( t - 33)\\\\\\\implies y =-\dfrac 3{125} t +\dfrac{99}{125} + \dfrac 65\\\\\\\implies y = -\dfrac 3{125} t +\dfrac{249}{125}

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2 years ago
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