All categories

4 years ago

Determine whether the relation is a function. (4,0), (4,1), (5,2), (6,3), (6,4)

Mathematics

1 answer:

Alexxandr [17]4 years ago

8 0

Answer:

The relation is not a function.

Step-by-step explanation:

In order for a relation to be a function, there can only be one output for every x value. If you were to graph this equation, it would not pass the vertical line test, as 4 has two outputs (0 and 1) and 6 has two outputs (6 and 4).

You might be interested in

To complete a job a crew of 8 people needs 18 days. How long will the same job be finished if the crew will have 9 people?

zavuch27 [327]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Indicate the equation of the given line in standard form, writing the answer below.

scZoUnD [109]

Answer: $y-\frac{11}{2}=6(x-2)$

Step-by-step explanation:

For it to bisect the segment, we need to find the midpoint.

The midpoint is $\left(\frac{-1+5}{2}, \frac{6+5}{2} \right)=\left(2, \frac{11}{2} \right)$ .

Now, for it to be perpendicular, we need to use the fact that perpendicular lines have slopes that are negative reciprocals of each other.

The slope of the given segment is $\frac{6-5}{-1-5}=-\frac{1}{6}$ , so the slope of the perpendicular bisector is 6.

Thus, the equation of the line in point-slope form is $\boxed{y-\frac{11}{2}=6(x-2)}$

4 0

2 years ago

there are 641 boys and 490 girls in Greenland school age child makes eight art pieces for classroom decorations all the art piec

Alexeev081 [22]

Answer:

133

Step-by-step explanation:

8 0

3 years ago

What number is 100,000 more than 75,000 and explain how u got answer

alina1380 [7]

100,000 + 75,000 = 175,000. To get the answer, you add the two.

6 0

3 years ago

If x = 4cosa and y = 5tana, find (x^2/16) - (y^2/25)

Cloud [144]

$x = 4 \cos(a)$

$\frac{x}{4} = \cos(a) \\$

$( { \frac{x}{4} })^{2} = ({ \cos(a) })^{2} \\$

$\frac{ {x}^{2} }{16} = {cos}^{2} (a) \\$

_____________________________________________

$y = 5 \tan(a)$

$\frac{y}{5} = \tan(a) \\$

$( { \frac{y}{5} })^{2} = ( { \tan(a) })^{2} \\$

$\frac{ {y}^{2} }{25} = {tan}^{2} (a) \\$

_____________________________________________

Thus ;

$\frac{ {x}^{2} }{16} - \frac{ {y}^{2} }{25} = \\$

${cos}^{2} (a) - {tan}^{2} (a)$

3 0

3 years ago