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2 years ago

What is the equation of a horizontal line that passes through the point (7, 11)

Mathematics

2 answers:

Vlad1618 [11]2 years ago

4 0

Your answer is D

A horizontal line is parallel to the x-axis and passes through all points in the plane with the same y-coordinate the equation is y = c where c is the value of the y-coordinate the line passes

Sure hope this helps you

Ksivusya [100]2 years ago

3 0

Answer:

y = 11

Step-by-step explanation:

A horizontal line passes through every single x - value, but only 1 y - value.

A vertical line hits every y-value and only 1 x-value.

The only y-value given is 11, so the equation is y = 11

-Chetan K

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poizon [28]

Part A
The given line passes through (-2,2) and it is parallel to the line

$4x - 3y - 7 = 0$

We need to determine the slope of this line by writing it in slope -intercept form.

$3y = 4x - 7$

$y = \frac{4}{3} x - \frac{7}{3}$
The slope of this line is
$\frac{4}{3}$

The line parallel to this line also has slope

$m = \frac{4}{3}$

The equation is

$y = \frac{4}{3} x + c$

We substitute (-2,2)

$2 = \frac{4}{3}( - 2) + c$

$c = 2 + \frac{8}{3} = \frac{14}{3}$

The required equation is

$y = \frac{4}{3} x + \frac{14}{3}$

PART B

The given line is

$4x - 3y - 7 = 0$

The slope of this line is
$\frac{4}{3}$

The slope of the line perpendicular to it is

$m = - \frac{3}{4}$

The equation of the line is

$y = - \frac{ 3}{4} x + c$

We substitute the point, (-2,2)

$2= - \frac{ 3}{4} ( - 2) + c$

$2= \frac{ 3}{2} + c$

$c = 2 - \frac{3}{2} = \frac{1}{2}$

The equation of the perpendicular line is

$y= - \frac{ 3}{4} x + \frac{1}{2}$

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